Given an array of ints, return the number of times that two 6's are next to each other in the array. Also count instances where the second "6" is actually a 7.
array667([6, 6, 2]) → 1
array667([6, 6, 2, 6]) → 1
array667([6, 7, 2, 6]) → 1
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public int array667(int[] nums) { int count=0; for (int i=0; i<nums.length-1;i++){ if ((nums[i]==6) && ((nums[i+1]==6) || (nums[i+1]==7))){ count++; } }return count; } |